How to Calculate the Radius of the Second Sphere in a Conductor Problem?

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SUMMARY

The problem involves calculating the radius of a second conducting sphere connected to a charged spherical conductor. The first sphere has a radius R1 and is charged to 28 kV, while the potential drops to 12 kV when connected to the second sphere. Using the equation V = kq/r, where k = 8.99e9, the relationship between the radii of the spheres can be established. The user attempted to solve for the radius of the second sphere, R2, and compared results from their calculations with those from a solutions manual, which indicated R2 = 2/3 R1.

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Homework Statement


A spherical conductor of radius R1 is charged to 28 kV. When it is connected by a long, very thin conducting wire to a second conducting sphere far away, its potential drops to 12 kV. What is the radius of the second sphere as a multiple of R1?


Homework Equations


V=kq/r
k=8.99e9


The Attempt at a Solution


Seems like it should be pretty simple. I just assigned variables q1=q2, k1=k2, v1=28kV and v2=12kV and solved for r (r=kq/V). Then compared the values of R. Webassign is giving me an incorrect answer. There was a similar problem and the book and using the books numbers i got R2=.6 R1 and the solutions manual said 2/3 R1 so I'm not sure if it's a rounding error or what. Just wanted to make sure I was doing it right since I only have 1 try left on webassign before I get locked out and lose easy points.

Thanks for any help in advance.
 
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