How to calculate the speed of an object attached to a string

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SUMMARY

The discussion focuses on calculating the speed of a 20-g bead attached to a 120 cm-long string, which acts as the radius of its circular path. The correct speed of the bead is determined to be 1.1 m/s. The bead's motion is characterized as three-dimensional, maintaining height while rotating, distinguishing it from a typical pendulum. The variable 'r' represents the horizontal separation of the object, which adds complexity due to the reuse of the variable name.

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aron silvester

Homework Statement


The question and the known/given variables are on the image in part 3. The question says that a 20-g bead is attached to a light 120 cm-long string. Now in my mind the bead will travel in a circular path if it is pushed really hard. So Isn't the length of the string, 120 cm, the radius of the circle? In my work, I had to solve for the radius. I found a solution online and this is their work. The correct answer is 1.1 m/s.

Homework Equations


It's in part 3 in the image.

The Attempt at a Solution


https://myhpu-my.sharepoint.com/per...R0RpKa0PGg&e=cf5a0f07109f401fb33a7a681a70fc4a
 
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The bead rotates in 3 D while keeping its height. It is not a typical pendulum. The r in the lower left part of the image is the horizontal separation of the object - the radius of the horizontal motion. It is a bit confusing that the same variable name is used again.

Edit: Picture for future reference:
physics question.jpeg
 

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mfb said:
The bead rotates in 3 D while keeping its height. It is not a typical pendulum. The r in the lower left part of the image is the horizontal separation of the object - the radius of the horizontal motion. It is a bit confusing that the same variable name is used again.

Wow, it makes so much sense now! Thanks!
 

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