MHB How to Calculate the Values of Other Trigonometric Functions Using Given Values?

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To calculate the values of other trigonometric functions from given values, it's essential to correctly interpret the conditions provided. In this case, with $\csc\theta = -2$ and $\cot\theta > 0$, the angle $\theta$ must be in the third quadrant. The correct approach involves using identities, starting with $\sin(\theta) = \frac{1}{\csc(\theta)}$, which leads to $\sin(\theta) = -\frac{1}{2}$. Subsequently, $\cos(\theta)$ is found using the Pythagorean identity, and the remaining functions can be derived from these values. This method is preferred as it applies broadly, even when the angle $\theta$ cannot be easily solved directly.
paulmdrdo1
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find the values of other five trig functions

$\csc\theta=-2\,and\, \cot\theta>0$

my solution

$x=-2$
$y=-1$

$r=\sqrt{5}$

$\displaystyle \sin\theta=-\frac{1}{\sqrt{5}}$

$\displaystyle\cos\theta=-\frac{2}{\sqrt{5}}$

$\displaystyle\cot\theta=2$

$\displaystyle\tan\theta=\frac{1}{2}$

$\displaystyle\sec\theta=-\frac{\sqrt{5}}{2}$

are they correct?
 
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it's not correct! use Pythagorean Identity involving sin and cos to find x.
 
Last edited:
I may have misunderstood your question, but your restrictions stated that $$\csc\theta=-2$$ whereas the value of your $\sin\theta$ was $-\frac{1}{\sqrt{5}}$, which most certainly does not satisfy $$\sin(x)=\frac{1}{\csc(x)}$$

*Edit* LATEBLOOMER beat me to it.
 
I just want to add the following:

We are told $$\csc(\theta)<0$$ and $$\cot(\theta)>0$$, and so we ask ourselves in which quadrant are both of these true. The cosecant function is negative in quadrants 3 and 4, while the cotangent function is positive in quadrants 1 and 3, so we now know $\theta$ must be in quadrant 3, i.e:

$$\pi<\theta<\frac{3\pi}{2}$$

Now, one way we could proceed is to simply solve for $\theta$ directly, and then evaluate the other 5 functions at that angle, or as suggested above, we may employ identities and definitions to get the other functions. It is usually the second of these methods that is preferred, because we won't always be able to easily solve for the angle $\theta$, and so this second method is a more general way to proceed.

If I were to solve this problem using this method, I would first look at:

$$\sin(\theta)=\frac{1}{\csc(\theta)}=?$$

Next, I would use:

$$\cos(\theta)=-\sqrt{1-\sin^2(\theta)}=?$$

Why do we take the negative root here?

Next, we may finish up with definitions:

$$\sec(\theta)=\frac{1}{\cos(\theta)}=?$$

$$\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=?$$

$$\cot(\theta)=\frac{1}{\tan(\theta)}=?$$

There are of course other Pythagorean identities that could be used, so my outline above is just one such way to go.
 
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