How to classify a quadratic surface?

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Homework Help Overview

The discussion revolves around classifying a quadratic surface defined by the equation 2x^2 + 4y^2 - 5z^2 + 3xy - 2xz + 4yz = 2. Participants explore the properties of quadratic forms and the process of determining the nature of the surface based on its eigenvalues.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formulation of the quadratic surface and the matrix representation of its coefficients. There is an exploration of finding eigenvalues and the significance of the right-hand side of the equation in classifying the surface.

Discussion Status

Some participants have provided guidance on the terminology and the process of finding eigenvalues. There is an ongoing exploration of how the eigenvalues relate to the classification of the quadratic surface, with some participants indicating potential classifications based on their findings.

Contextual Notes

Participants are considering the implications of the right-hand side of the equation and its effect on the classification of the surface, as well as the need for clarity in the terminology used during the discussion.

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Homework Statement



Classify the quadratic surface:

2x^2 + 4y^2 - 5z^2 + 3xy - 2xz + 4yz = 2

Homework Equations



A quadratic form is a second degree polynomial equation in three variables which has the form

F(x,y,z) = ax^2 + by^2 + cz^2 + 2dxy + 2exz + 2fyz

where coefficients a through i are real numbers.

The curve F(x,y,z) = j can be written in the form (x^T)*A*x = j where

x = [x, y, z]

A = [a, d, e]
[d, b, f]
[e, f, c]

The Attempt at a Solution



A = [2, 3/2, -1]
[3/2, 4, 2]
[-1, 2, -5]

Then, find the eigenvectors of A-tI...check how many are positive, negative, or 0 and classify using the information? Is that the right way to proceed?
 
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cookiesyum said:
Then, find the eigenvectors of A-tI...check how many are positive, negative, or 0 and classify using the information? Is that the right way to proceed?

I think you have the right idea, but the wrong terminology: You are trying to find the eigenvalues of A by finding zeros of the polynomial det(A-tI).
 
yyat said:
I think you have the right idea, but the wrong terminology: You are trying to find the eigenvalues of A by finding zeros of the polynomial det(A-tI).

Oh ok. And then, the fact that F(x, y, z) is = 2 doesn't make a difference, right? Because, it is the j that F(x, y, z) can be set equal to such that (x^T)*A*x = j?
 
cookiesyum said:
Oh ok. And then, the fact that F(x, y, z) is = 2 doesn't make a difference, right? Because, it is the j that F(x, y, z) can be set equal to such that (x^T)*A*x = j?

The sign of the RHS does make a difference, in this case it tells you how many "sheets" the quadratic surface has (have you found the eigenvalues yet?).
 
yyat said:
The sign of the RHS does make a difference, in this case it tells you how many "sheets" the quadratic surface has (have you found the eigenvalues yet?).

I get two positive and one negative eigenvalues: -5.647, 1.661, 4.986. This would be a hyperboloid of one sheet.
 
cookiesyum said:
I get two positive and one negative eigenvalues: -5.647, 1.661, 4.986. This would be a hyperboloid of one sheet.

That's correct. :smile:
 
yyat said:
That's correct. :smile:

Thanks a bunch!
 

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