- #1
JD_PM
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Homework Statement
We know that
$$< (x_1 - x_2)^2 > = \frac{K_bT}{K}$$
$$< (x_2 - x_3)^2 > = \frac{K_bT}{\gamma}$$
What's ##< (x_3 - x_1)^2 >## equal to?
Homework Equations
The Attempt at a Solution
I have tried: ##< (x_2 - x_3)^2 > - < (x_1 - x_2)^2 >## but did not get ##< (x_3 - x_1)^2 >##
How can I get it?
Thanks
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