- #1

ChiralSuperfields

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- 136

- Homework Statement
- Please see below

- Relevant Equations
- Please see below

For this problem,

The solution is,

However, I tried to solve this problem using my Graphics Calculator instead of completing the square. I got the zeros of ##x^2 - 2x - 4## to be ##x_1 = 3.236## and ##x_2 = -1.236##

Therefore ##x_1 ≥ 3.236## and ##x_2 ≥ -1.236##

Since ##x_1 > x_2## then,

Therefore ## (x | x ≥ -1.236 ) ## which is ##~(x | x ≥ 1 - \sqrt{5} )~## (sorry curly brackets were not working), however, my domain restriction excludes some other values shown in the solution. Dose anybody please know a way using my method to get those values?

Many thanks!

The solution is,

However, I tried to solve this problem using my Graphics Calculator instead of completing the square. I got the zeros of ##x^2 - 2x - 4## to be ##x_1 = 3.236## and ##x_2 = -1.236##

Therefore ##x_1 ≥ 3.236## and ##x_2 ≥ -1.236##

Since ##x_1 > x_2## then,

Therefore ## (x | x ≥ -1.236 ) ## which is ##~(x | x ≥ 1 - \sqrt{5} )~## (sorry curly brackets were not working), however, my domain restriction excludes some other values shown in the solution. Dose anybody please know a way using my method to get those values?

Many thanks!

Last edited: