How to compute how much energy is released in nuclear fusion?

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To compute the energy released in nuclear fusion, the initial step involves calculating the mass loss using the equation Δm = m(1^2H) + m(1^3H) - m(2^4He) - m(0^1n), resulting in a mass loss of 0.0188828u. This mass loss translates to a reaction energy of approximately 2.81 x 10^-12 J per fusion reaction. However, the total energy released per kilogram is significantly higher, estimated at about 3.4 x 10^14 J. The discrepancy arises from the need to consider the number of reactions occurring in a given mass of fuel. Understanding the energy per reaction versus the total energy output per kilogram is crucial for accurate calculations in nuclear fusion energy.
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Homework Statement
In a fusion power plant, it is planned to use deuterium and tritium, so that one gets helium and neutrons. How much one gets energy if we have $1\textrm{ kg}$ fuel?
Relevant Equations
$\Delta m=m(_1^2\textrm{H})+m(_1^3\textrm{H})-m(_2^4\textrm{He})-m(_0^1\textrm{n})$
I thought the first step is to compute the loss of mass. ##\Delta m=m(_1^2\textrm{H})+m(_1^3\textrm{H})-m(_2^4\textrm{He})-m(_0^1\textrm{n})=2.0141018u+3.0160493u- 4.0026033u-1.0086650u=0.0188828u##. The corresponding reaction energy is ##0.0188828 \cdot 931,5MeV=17.54MeV\approx 2.81\cdot 10^{-12}J##. But the answer is about ##3.4\cdot 10^{14}\textrm{ J}##. What is my mistake?
 
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If the energy per reaction is 2.81e-12 J, what is the energy per kg?
 
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