How to count all ways to arrange Bosons?

  • Thread starter Thread starter benagastov
  • Start date Start date
  • Tags Tags
    Bosons Count
benagastov
Messages
8
Reaction score
0
Homework Statement
This is very basic question but to be honest I dont understand even though I read Pointon's book. The question said what is all possible ways to arrange Bosons and how much is the total configuration. The energy states/levels are = 1E, 2E, and 3E. The total of boson particles are 2, and all of the states should have degeneracy/g_j = 3 and total Energy E = 4.

Is my answer incorrect? Thank you
Relevant Equations
W = \frac{(n+g-1)!}{n!(g-1)!}
Capture2.JPG
 
Physics news on Phys.org
In your enumeration of states, you are missing one case.

Your calculation on the right is correct only for distinguishable particles. This should not apply to identical bosons.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top