How to Create a Pop-Up Effect with Paper?

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To create a pop-up effect with paper, start with a sheet and draw eight parallel lines perpendicular to its length. Fold the paper in an accordion style, alternating the direction of each fold. Stack the folded paper on the ground and release it to achieve the popping effect, ensuring not to crease the folds excessively. Over-creasing will limit the paper's ability to exert a restorative force, similar to bending wood. This method allows the paper to push light objects upwards effectively.
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Hi can anyone tell me how to make a paper pop out ? something like the picture here .
 

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  1. Get a sheet of paper.
  2. Draw approximately 8 parallel lines perpendicular to the length of the sheet of paper.
  3. At each line, fold the paper, alternating the direction of the fold ("accordion" style).
  4. Put the paper on the ground such that all folds are stacked on top of one another.
  5. Let go - the paper will pop out, as long as you did not crease the folds too much.
 
lol sorry , my explanation skill and english is not that good . I mean , it would pop up like rubber , some force that pushes it up .
 
Paper is not very elastic, but if you try what saketh said, and don't fold the paper too much, then it might work. folding the paper too much will deform the paper too far beyond its limited elastic range.
 
crays said:
lol sorry , my explanation skill and english is not that good . I mean , it would pop up like rubber , some force that pushes it up .
If you crease the folds too much, then the paper will be unable to exert a significant restorative force. Picture the paper as a thin slice of wood. If you bend the wood, it will exert a restorative force against the bending force. If the bending force exceeds a certain critical limit, the wood will break and the restorative force goes to zero. Similarly, creasing the paper too much will "break" it.

After doing what I said in my post above, you will find that the paper will be able to push light things upwards. Don't ask me how to theoretically calculate the restorative force - empirical calculation is the way to go.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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