How to create good quantum states from good quantum numbers?

Click For Summary
SUMMARY

This discussion focuses on creating "good" quantum states from "good" quantum numbers within the context of degenerate perturbation theory. It establishes that for a perturbation H', the quantum numbers l, s, j, and mj are considered "good" if they commute with H'. The conversation specifically addresses the construction of "good" states for the strong field Zeeman effect and fine structure correction, represented as | n l ml s ms > and | n l s j mj >, respectively. The method for transitioning from | n l s j mj > to the sum involving Clebsch-Gordan coefficients is highlighted as a key solution.

PREREQUISITES
  • Understanding of degenerate perturbation theory
  • Familiarity with angular momentum in quantum mechanics
  • Knowledge of Clebsch-Gordan coefficients
  • Basic concepts of quantum states and quantum numbers
NEXT STEPS
  • Study the application of Clebsch-Gordan coefficients in quantum mechanics
  • Explore the strong field Zeeman effect and its implications
  • Learn about fine structure corrections in quantum systems
  • Investigate the mathematical framework of angular momentum addition
USEFUL FOR

Quantum physicists, graduate students in physics, and researchers focusing on quantum mechanics and perturbation theory will benefit from this discussion.

mattlorig
Messages
24
Reaction score
0
how to create "good" quantum states from "good" quantum numbers?

I think I am finally understanding what the "good" quantum numbers are in degenerate perturbation theroy. Basically, given a perturbation H', if
[H', L^2] = [H', S^2] = [H', J^2] = [H', Jz] = 0, then
l, s, j, and mj are the "good" quantum numbers.

But, I'm a little confused as to how one goes about creating a "good" quantum state from the "good" quantum numbers.

In particular, I'm wondering about how to create a "good" states for the strong field Zeeman effect ("good" state = | n l ml s ms > ) and the fine structure correction ("good state = | n l s j mj > ).

i.e. how do I go from: | n l s j mj > to SUM( c R_nl Y_lm |s ms> )?
 
Physics news on Phys.org
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K