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How to deal with INVERSE TANGENT?

  • Thread starter bmed90
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  • #1
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Homework Statement



Find X. Given the following Equation


2.094 radians =tan^-1(2*x*(1.11)/1-(1.11)^2)

Homework Equations





The Attempt at a Solution



How do you get rid of inverse tangent?

Here's what i got

tan(2.094((180/pi))*(1-(1.11)^2) / 2*1.11 = X
 
Last edited:

Answers and Replies

  • #2
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5,191

Homework Statement



Find X. Given the following Equation


2.094 radians =tan^-1(2*x*(1.11)/1-(1.11)^2)
This -- (2*x*(1.11)/1-(1.11)^2) -- is missing some parentheses.

Is it supposed to be this?
$$ \frac{2x \cdot 1.11}{(1 - 1.11)^2}$$

Homework Equations





The Attempt at a Solution



How do you get rid of inverse tangent?
Take the tangent of both sides.
Here's what i got

tan(2.094((180/pi))*(1-(1.11)^2) / 2*1.11 = X
 
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  • #3
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No, the 1.11 in the denominator is squared instead of (1-1.11)^2

So the denom is

(1-(1.11)^2)


Sorry my mistake
 
  • #4
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You are doing the right thing, taking the tangent of both sides. However you do not want to use the ##180/\pi## which converts radians to degrees. (Also, if you really wish to convert back to degrees, you have to convert everything, not just one factor. )

Usually if there is an x involved we assume we are in radians, which are really arclength, and so compatible with lengths on the x-axis.

Go ahead and compute it out.
 
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