How to define change of angular momentum in non-isolated system?

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Homework Help Overview

The discussion revolves around the definition and calculation of angular momentum in the context of a non-isolated system, specifically related to a problem involving a snowball and its effect on torque and angular momentum.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between torque and angular momentum, questioning the calculation of torque as mvL and discussing the implications of momentum direction on angular momentum.

Discussion Status

Some participants have clarified the distinction between angular momentum and torque, while others are considering how the direction of momentum affects the overall angular momentum of the system. There is an ongoing exploration of these concepts without a definitive resolution.

Contextual Notes

The discussion references a specific problem from a physics course, indicating that there may be constraints or specific conditions outlined in the original problem statement that are not fully detailed in the thread.

DannyPhysika
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Homework Statement



http://tycho.physics.wisc.edu/courses/phys201/fall06/Discussion/Disc14Solution.pdf

problem 38, part b)

Homework Equations



I final w final = I initial w initial

The Attempt at a Solution



I understand that the snowball is introducing a net torque and I know that torque = (force applied) x (distance from axis of rotation) (in this case). I am just unsure how the torque was calculated as mvL. I know L is the distance, but isn't mv the momentum of the ball?
 
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mvL is angular momentum, not torque. Angular momentum is defined as r x p, where r is the position vector and p is the momentum of the object. In this case, r is perpendicular to p, so it makes sense that angular momentum would be mvL.
 
ideasrule said:
mvL is angular momentum, not torque. Angular momentum is defined as r x p, where r is the position vector and p is the momentum of the object. In this case, r is perpendicular to p, so it makes sense that angular momentum would be mvL.

Ok that makes sense. If the ball were coming from the right side would we add mvL instead, because the momentum being added to the system is in the same direction of its initial angular momentum?
 
Yes, that's correct.
 
Thanks :)
 

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