How to define the domain of a 2-variable function as this?

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The domain of the two-variable function f(x,y) = x + y is defined based on the conditions set for x and y. Specifically, for any given y, f(x,y) is defined on the interval [0, g(y)), and for any given x, it is defined on [0, h(x)). The general formulation for the domain D is D = {(x,y) ∈ R² | x ∈ [0, g(y)) and y ∈ [0, h(x))}. However, the discussion reveals a contradiction in the initial conditions, leading to the conclusion that the function is only defined for the specific case D = {(0,0)} or potentially the entire real plane depending on the interpretation of the intervals.

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Hi,

I am wondering how to express the domain of a two-variable function f(x,y) as below.

For any given y, f(x,y) is defined on [0, g(y)); for any given x, f(x,y) is defined on [0, h(x)). Then how should I specify the domain for the function f(x,y)?

To be more specific, f(x,y)=x+y, and for any given y, it is defined on [0, y); for any given x, it is defined on [0, x). I want to know what is the domain of f(x,y).

Thanks.
 
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the domain D is in general

[itex]D=\{(x,y)\in R^2| x \in[0,g(y))[/itex] and [itex]y \in [0,h(x))\}[/itex]

I don't think that without knowing more about h and g you can say more than this which is just a tidier formulation of what you say in your post.

and in the specific case:

[itex]D=\{(0,0)\}[/itex]

maybe even this is excluded since does [0,0) include 0 or not...

Anyway the example says in fact that f(x,y) is only defined for x and y greater or equal zero and x<y and y<x (with the exception above depending on [0,0) including 0 or not).

although the function x+y is then quite arbitrarily restricted since we can easily define that on all of the real plane

Actually now that I think about it the statement is rather contradictory since you say for any given y the function is defined on [0,y) so for instance f(3,4) should then be defined. but you say for any given x it is defined on [0,x) so f(3,4) should not be defined. unless you mean something like at least defined for this and that in which case the formulation of the problem is a bit weird and the answer would simply be:
D is the real plane

and in general

[itex]D=\{(x,y)\in R^2| x \in[0,g(y))[/itex] or [itex]y \in [0,h(x))\}[/itex]

I hope this helps!
 
Thanks a lot for your reply.

Yes, you are right. My initial statement is contradictory and not well-defined. Now I have cleared my mind with your comments. Thanks again.
 

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