How to Derive the Differential Equation for Forced, Damped Oscillations

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Homework Help Overview

The problem involves deriving a differential equation for a system representing a car oscillating vertically on a washboard road surface. The context includes forced, damped oscillations, with the car modeled as a mass on a spring connected to a dashpot.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between the variables y(x) and y(t), questioning the implications of comparing these two functions. They express confusion about the derivation of the differential equation and the physical setup of the problem. Other participants raise concerns about whether the question is appropriately placed in the forum.

Discussion Status

The discussion is ongoing, with the original poster seeking clarification on the derivation process and expressing uncertainty about their approach. There is no clear consensus, but participants are engaging with the problem and exploring its components.

Contextual Notes

The original poster indicates a need for prompt assistance, suggesting a time constraint that may affect the depth of exploration in the discussion.

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Homework Statement


Hi. The problem is question 1(a) in the file below:
http://www.mth.uct.ac.za/Courses/MAM24678/mod2od/Project1_07.pdf


The Attempt at a Solution



Question 1(a) is the one I have a problem with. I just don't know what he's getting at. Is y(x) the function that describes the road? And comparing y(t) and y(x) implies, to me, that x=vt, so it has a constant velocity with respect to the x-axis; a very odd thing to do...
Is Y then the vertical displacement of the vehicle from the x-axis? So the car is like a mass on a spring ,on the road? I have no idea how he derived that Differential Equation.

Please, any help on deriving the differential equation would be great

Any help is much appreciated thanks.

(P.S. I need this pronto please !)

Ok, what I did. First I said:
Y = y + p + l
l is the relaxed length of the spring (a constant), and p is the displacement from the equilibrium position of the mass on the spring. If you re-write:
p = Y - y - l
then find the equation of motion of the mass on the spring:
m[d^2(p)]/dt^2 = -kp -c(dp/dt)

And plugging in p = Y - y -l, but this does not give the correct answer. I really do not know how to get the differential equation, help please!
 
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I'm wondering- is this in the correct section? Should I have posted this elsewhere?
 
Ok, I'll just write out the question here:

Suppose that a car oscillates vertically as if it were a mass m on a single spring with constant k, attached to a single dashpot (dashpot provides resistance) with constant c. Suppose that this car is driven along a washboard road surface with an amplitude a and a wavelength L (Mathematically the 'washboard surface' road is one with the elevation given by y=asin(2*pi*x/L).)

(a) Show that the upward displacement of the car Y satisfies the equation:

[tex]m\ddot{Y} + c\dot{Y} + kY = c\dot{y} + ky[/tex]

where y(t) = asin(2*pi*v*t/L)
and v is the velocity of the car.
 
Please, anyone?
 

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