How to Determine Convergence Intervals for Different Laplace Transforms?

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SUMMARY

This discussion focuses on determining convergence intervals for various Laplace transforms, specifically for functions like \( e^{at} \), \( \sin(at) \), and \( \cos(at) \). The key takeaway is that the region of convergence for \( \mathcal{L}\{e^{at}\} \) is defined as \( Re(s) > Re(a) \) when \( a \) is a complex number. This contrasts with the case where \( a \) is real, leading to convergence intervals of \( Re(s) > a \) for real \( a \) and \( Re(s) > 0 \) when \( a = ix \) with \( x \) being real.

PREREQUISITES
  • Understanding of Laplace transforms, specifically \( \mathcal{L}\{f(t)\} \)
  • Familiarity with complex numbers and their properties
  • Knowledge of Euler's identity \( e^{ix} = \cos x + i\sin x \)
  • Basic concepts of regions of convergence in complex analysis
NEXT STEPS
  • Study the properties of Laplace transforms for complex functions
  • Learn about regions of convergence in complex analysis
  • Explore the implications of Euler's identity in signal processing
  • Investigate the application of Laplace transforms in solving differential equations
USEFUL FOR

Mathematicians, engineers, and students studying control systems or signal processing who need to understand the behavior of Laplace transforms in complex domains.

matematikuvol
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##\mathcal{L}\{f(t)\}=F(s)##

[tex]\mathcal{L}\{e^{at}\}=\frac{1}{s-a},Re(s)>a[/tex]
[tex]\mathcal{L}\{\sin (at)\}=\frac{a}{s^2+a^2}, \quad Re(s)>0[/tex]
[tex]\mathcal{L}\{\cos (at)\}=\frac{s}{s^2+a^2},Re(s)>0[/tex]

If we look at Euler identity ##e^{ix}=\cos x+i\sin x##, how to get difference converge intervals ##Re(s)>a## and ##Re(s)>0##?
 
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matematikuvol said:
[tex]\mathcal{L}\{e^{at}\}=\frac{1}{s-a},Re(s)>a[/tex]
The problem is that you haven't defined things precisely enough. In this line you are assuming a is real, so the region of convergence only holds for real a. If you allow a to be a general complex number (which is required for your complex exponentials) then you get,
[tex]\mathcal{L}\{e^{at}\}=\frac{1}{s-a},Re(s)>Re(a).[/tex]

If [itex]a = i x[/itex] with real [itex]x[/itex], then [itex]Re(a)=0[/itex] so the region of convergence is [itex],Re(s)>0[/itex].


jason
 

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