How to Determine Velocities After a Collision in a Physics AP Mechanics Problem?

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Homework Help Overview

The discussion revolves around a physics problem involving a collision between a ball and a cube on a frictionless table. The ball, initially at rest, is struck by a moving cube, and participants are tasked with determining the velocities of both objects immediately after the collision.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of momentum equations to analyze the collision, questioning whether the collision is elastic and how to find the velocities post-collision. There is also mention of using impulse from a provided graph to aid in calculations.

Discussion Status

Multiple interpretations of the collision type are being explored, with some participants suggesting it may be elastic while others argue against it. Guidance has been offered regarding the use of momentum conservation, and some participants have shared their calculations for the velocities.

Contextual Notes

Participants express confusion about the relationship between impulse and the type of collision, and there is a focus on the implications of the graph related to the force exerted during the collision.

  • #31
Um... the one problem i still have is everyone is saying equations that i do understand, but there are always two unknowns (v1 and v2) and someone said I already knew one---but I don't. So my real problem is finding one of them so I can find the other... If I have to use 2 equations and solve, what two equations can I set up?
 
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  • #32
Part d of the problem says: Determine the kinetic energy dissipated in the collision.

I know kinetic energy was lost, because it was an inelastic collision, but when I do it out I get that no kinetic energy is lost:

before collision:
(1/2)(.5)(26^2)+(1/2)(5)(0) = 169

after collision:
(1/2)(.5)(21.27^2) + (1/2)(5)(4.727^2) = approx. 169

I'm assuming I got this incorrect result because the velocities I used (21.27 and 4.727) are incorrect---because the collision would have to be elastic for them to be correct, and thus it makes sense that in an elastic collision the energy would be conserved... So basically this goes back to my last post----I need to find the correct v1 and v2... Can anybody help? Please!
 
  • #33
physicsgirl101 said:
Part d of the problem says: Determine the kinetic energy dissipated in the collision.

I know kinetic energy was lost, because it was an inelastic collision, but when I do it out I get that no kinetic energy is lost:

before collision:
(1/2)(.5)(26^2)+(1/2)(5)(0) = 169

after collision:
(1/2)(.5)(21.27^2) + (1/2)(5)(4.727^2) = approx. 169

I'm assuming I got this incorrect result because the velocities I used (21.27 and 4.727) are incorrect---because the collision would have to be elastic for them to be correct, and thus it makes sense that in an elastic collision the energy would be conserved... So basically this goes back to my last post----I need to find the correct v1 and v2... Can anybody help? Please!

Ok, you know F*t = m(Vf - Vi)

you already know F*t = 12 from the graph... and you know the ball was initially at rest... You also know the mass of the ball... I'm sure you can solve for vf, which gives you one of the velocities of the 2 objects...
 
  • #34
Thank you so much, APchemstudent! i can't believe i didnt catch that... i think I am in overload... :) THANKS!
 
  • #35
Alright... After a lot of work, this is what I got:
immediately after the collision:
speed of ball: 2.4m/s
speed of cube: 2m/s (going to the right---the same direction as the ball*)

I then gathered that 153.6 Joules of kinetic energy was lost in the collision...

How does that all sound? (especially the direction of the ball??)
 
  • #36
physicsgirl101 said:
Alright... After a lot of work, this is what I got:
immediately after the collision:
speed of ball: 2.4m/s
speed of cube: 2m/s (going to the right---the same direction as the ball*)

I then gathered that 153.6 Joules of kinetic energy was lost in the collision...

How does that all sound? (especially the direction of the ball??)

everything looks perfect...
 
  • #37
Yay! I'm so excited, thank you, everyone!
 
  • #38
there was another part of the question which asks the distance between the two spots of initial impact on the ground (cube and ball)... if anyone cares to do it... i got 4.178 meters-----anyways, I am glad to be done, thanks for all the clarifications!
 

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