How to Evaluate and Solve Riemann Sums for Integration: Step-by-Step Guide

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The discussion focuses on evaluating the integral $\int_{0}^{\frac{\pi}{2}} \cos^2(2\pi n x) dx$ using Riemann sums. A participant expresses confusion about substituting values and applying the power of sums formula, particularly with the variable "i" appearing in the cosine function. Another contributor suggests that using Riemann sums may complicate the evaluation process and recommends leveraging the trigonometric identity $\cos^2(\theta) = \frac{1}{2}(1 + \cos(2\theta))$ for simplification. The conversation highlights the challenges of self-taught integration methods and the potential for more straightforward approaches. Ultimately, using known anti-derivatives and identities can streamline the integration process.
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Homework Statement


Evaluate and give an exact answer.

$\int_{0}^{\frac{Pi}{2}\right)}cos^2(2*Pi*n*x)dx where n is a positive integer.


Homework Equations





The Attempt at a Solution


(change)x=\frac{b-a}{n}\right)=\frac{Pi}{2n}\right)
and...
x_i=a+i(change)x

I'm not sure how to write a Riemann Sum in latex code, so I'll be using "S" as the notation for the Riemann Sum (i=1, n): f(x_i)*(b-a)/n

I used the limit as n -> oo definition of an integral:

$\int_{0}^{\frac{Pi}{2}\right)}cos^2(2*Pi*n*x)dx=lim(n->oo)S[f(x_i)(\frac{b-a}{n}\right))]

Next I substituted the values of x_i:

lim(n->oo)S[f(\frac{ib}{n}\right))(\frac{Pi}{2n}\right))]

Then evaluated f(x_i):

lim(n->oo)S[cos^2(2*Pi*n*\frac{Pi}{2n}\right)]

Here is where i get a bit confused. In the example with n-subintervals that I worked through in my book, it substituted the value of the Riemann sum of i using the power of sums formula, however, I end up with "i" inside of the cosine function, and am not sure how to finish evaluating the integral.

Other examples in the book had the value of n defined, thus making the integration process much more simple.

Am I even doing the right thing? Bare with me, my integration is self taught.
 
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Why are you trying to change to Riemann sums? That is, at best, a very difficult way of evaluating integrals! (Though excellent for thinking how to set up integrals for applications.)

Do you know the anti-derivatives of sine and cosine themselves? If so you can use the trig identity cos^2(\theta)= (1/2)(1+ cos(2\theta).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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