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OK, that's better. But so far you've not placed any restrictions on those events.John Huang said:Thanks for your correction. Now, I will rewrite my sentence.
How do observers everywhere in the stationary system S measure the "time period" Δt of ONE SPECIFIC SECTION of continuous events from event 1 at point A to event 2 at point B? They use the synchronized stationary clocks in S. For the observers everywhere in the moving system S', they will use the synchronized moving clocks to measure the "time period" Δt' from event 1 to event 2. Now, we have a better defined case.
OK. I assume by 'easy way' you mean for there to be observers in both frames at the location of the events so that they do not have to account for light travel time. Good.There are two ways to do the measure jobs.
The easy way is to measure event time t1 and t1' for event 1 at point A and measure event time t2 and t2' for event 2 at point B. We will have Δt' = t2'-t1' and Δt = t2-t1.
OK, these single observers must take light travel time into account when interpreting their direct observations. So what? The two methods of measuring the time intervals between those events will give the same answer. (What is your point in mentioning these "two ways"?)The difficult way is to measure event time by assigned observers, one in S and one in S'. The simplest assginment is let them stay at origin points O and O'.
OK, now you have restricted the pair of events to be events that take place at the same location in S'. (At least that's what I think you mean.)Let us look at this simplest situation. Since the distances of each pair of four points A, B, O and O' could be different, we must adjust the influence of the distance. When A=B=O', it will be the situation arranged by Einstein. We will have Δt' = t2'-t1' and Δt = t2-t1.
No. You are incorrect in thinking that those methods (using the time dilation formula or using the LT) yield different results.For this SPECIFIC SET of t1,t2, t1' and t2', SR states based on the relative speed "v", the relation of the speed of time in S' and S should be Δt' = Δt/γ, but regarding the "time period", we should go by Δt' = γ(Δt-(vΔx/c^2)). Am I correct?
In this particular case, you can relate the time intervals using the time dilation formula since the events take place at a single location in S'. So Δt' = Δt/γ is perfectly correct.
Or you can use the LT: Δt = γ(Δt' + (vΔx'/c^2)). Since Δx' = 0, we are back to the same result, Δt' = Δt/γ.
Sure, for the simple case in question, the time dilation formula applies just fine. Of course, you get the same result by applying the full Lorentz transformation.Yes, "In words, the time dilation formula says that 'moving clocks run slow'." and for relative speed v, the time dilation formula Δt' = Δt/γ stands.
Δt' and Δt represent the time interval between those two events as seen in different frames.In Δt' = Δt/γ, Δt' is for the time period in the moving system S' of a given SECTION OF EVENTS and Δt is for the stationary system S of the same SECTION OF EVENTS.
I'm still not getting what your point is. And you still seem to speak as though you think "SR" just means time dilation. There is more going on than that. What about length contraction? What about the relativity of simultaneity? Sure, in certain special cases (like the one discussed here) you can directly apply the time dilation formula. But in general you must include all three relativistic effects. And the LT does that for you automatically.