How to Factor Polynomials with Three Terms?

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The discussion revolves around factoring the polynomial x^2(a+b) - x(a+b) + (a+b). The initial approach involved attempting decomposition, but the correct method was to factor out the common term (a+b), leading to (a+b)(x^2 - x + 1). It was clarified that the polynomial inside the brackets does not have real roots, confirming that the factorization is complete. The participants concluded that the polynomial cannot be factored further into real numbers. The exchange highlights the importance of recognizing the absence of real roots in polynomial factorization.
Hollysmoke
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I'm having trouble with this one factoring problem-

x^2(a+b)-x(a+b)+(a+b)

I thought it was 3 terms so I tried to do decomposition but it doesn't seem to work. If someone could just help me, I'd appreciate it. Thanks!
 
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Take out the common factor (a+b) first.
 
so I'm going to end up (a+b)(x^2-x)?
 
No. If you multiply that out, would you have any constant term?
 
OH! so (a+b)(x^2-x+1)
 
Quite right!
So, what are the roots of the polynomial hiding inside the brackets?
 
I'm not sure but its impossible to multiply to -1 and add to 1
1*1=1 and add to 2, 1*-1=-1 but add to 0
so I can't use quadratics...
 
So, you've found that your polynomial hasn't got any real roots, right?
That means your factorization is complete..
 
Hey hey! Thank you for your help ^_^
 

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