How to Find a Vector Passing Through Two Points with Equal Magnitude?

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To find a vector passing through the points (1,1,1) and (3,4,5) with a magnitude of √3, start by treating (1,1,1) as the vector's origin and (3,4,5) as its endpoint. Subtract the coordinates to obtain the direction vector, which is (2,3,4). The magnitude of this vector is calculated using the formula √(x²+y²+z²), resulting in a value greater than √3. To achieve the desired magnitude, scale the vector appropriately. The solution can be simplified by focusing on the three-dimensional aspect without overcomplicating the problem.
AlchemistK
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Homework Statement



|Vp| = \sqrt{}3

Find a vector which is passing through (1,1,1) and (3,4,5) whose magnitude is equal to vector P.


I have started studying vectors, and know the vector algebra rules, thought i do not understand the use of coordinates in order to find the direction.



Thank you.
 
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AlchemistK said:

Homework Statement



|Vp| = \sqrt{}3

Find a vector which is passing through (1,1,1) and (3,4,5) whose magnitude is equal to vector P.


I have started studying vectors, and know the vector algebra rules, thought i do not understand the use of coordinates in order to find the direction.


Thank you.

Certainly you can think of (1,1,1) as the start of your vector, then (3,4,5) as the end of your vector...thus subtraction yields a vector that passes through both points, just with a certain magnitude.

The magnitude of a vector is given as sqrt(x^2+y^2+z^2)...you can find that you won't get a magnitude of sqrt(3) right away...think of a way you can "scale" the vector to make it the right magnitude...
 


Thanks. I figured out the answer and in fact it was quite easy, i just started thinking a lot ,the question being in three dimensions, and hence veered away from the actual solution.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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