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OK, well this is probably a pretty basic problem. I understand all of it except for one part.
If [tex]F(x)=\int^{x}_{0} sin(t)dt[/tex], where x [tex]\geq[/tex] 0, what is the maximum value of F?
[tex]F(x)=\int^{x}_{0} sin(t)dt[/tex]
[tex]F(x)=\int^{x}_{0} sin(t)dt = -cos(x) + c[/tex]
max = 1 + c
How do you find c?
If solving with a graphing calculator: [tex]y^{}_{1} = Fnint(sin(t),t,0,x)[/tex] then the answer is 2; I just don't know how the calculator found the shift.
Homework Statement
If [tex]F(x)=\int^{x}_{0} sin(t)dt[/tex], where x [tex]\geq[/tex] 0, what is the maximum value of F?
Homework Equations
[tex]F(x)=\int^{x}_{0} sin(t)dt[/tex]
The Attempt at a Solution
[tex]F(x)=\int^{x}_{0} sin(t)dt = -cos(x) + c[/tex]
max = 1 + c
How do you find c?
If solving with a graphing calculator: [tex]y^{}_{1} = Fnint(sin(t),t,0,x)[/tex] then the answer is 2; I just don't know how the calculator found the shift.