The displacement between 15 and 20 seconds in a position vs. time graph is calculated by subtracting the position at 15 seconds (51 meters) from the position at 20 seconds (60 meters), resulting in a displacement of 9 meters. This calculation is valid regardless of whether the motion involves constant velocity or constant acceleration. The fundamental principle is to determine the difference in position over the specified time interval.
PREREQUISITESStudents studying physics, particularly those focusing on kinematics and motion analysis, as well as educators looking for clear explanations of displacement calculations.
kjohnson said:It doesn't matter if its constant velocity, constant acceleration, etc. They just want to know how far the object displaced over that time. So your just taking the displacement at time 'b' minus the displacement at time 'a'.
60m-51m=9m