Position in Velocity-Time Graphs

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SUMMARY

The discussion centers on calculating the position of an object using a velocity-time graph. Multiplying time by velocity, such as 2 seconds by 1 m/s, yields a change in position of 2 meters, confirming that this method is valid for constant velocity scenarios. Additionally, the area under the curve of the graph represents the total displacement, with negative areas indicating movement in the opposite direction. This approach is fundamental in kinematics for determining an object's position over time.

PREREQUISITES
  • Understanding of basic kinematics principles
  • Familiarity with velocity-time graphs
  • Knowledge of area calculation under curves
  • Concept of displacement and its relation to velocity
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  • Study the relationship between acceleration and velocity in motion
  • Learn about integrating velocity functions to find displacement
  • Explore the implications of non-constant velocity on position calculations
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crownedhues
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Homework Statement
How do I find the position of an object in a velocity-time graph?
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Would it be correct if I multiplied the time by the velocity of the object since the units would cancel into meters? So for example, I multiply 2 seconds by 1m/s which gives me 2m - would that be the object's position?
 
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If the velocity is constant, that will give you the change in position.
More generally, take the area under the curve (counting as negative where the velocity is negative).
 

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