How to find empirical formula from combustion equation

[RockenNS42]

Homework Statement

The organic solvent thiophene is a carbon-hydrogen-sulfur compound that makes C02, H20 AND S02 when burned in excess Oxygen. When subject to combustion analysis, a 1.3020g sample makes 2.7244 g CO2, .5575G H20 and .99151 SO2. Find the empirical formula of thiophene

Homework Equations

None?

The Attempt at a Solution

so first i wrote out the combustion

Thiophene + O2 <> CO2+ H20+SO2 but i can't balance it yet


I then found the amount of moles the compunts on the right side


CO2= 2.772g/44.009g/mol = .06186 moles / .00309 ~ 20 mol
H20= .5575g/18.019g/mol= .00309mole / .00309 = 1 mol
SO2=.9915g/64.045g/mol = .01548 mole / .00309 ~5 mol


therefore

Thiophene + O2 <> 20(CO2)+ H20+5(SO2)

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But I have no idea where to go from here, anyone have any hints?

 

[zainriaz]

first try to find the percentage of carbon from CO2 and hydrogen from h20 and sulphur from so2 then calculae percentage of oxygen from it.
now find mole of each element from its percentage .then find its atomic ratio.this would give the value o empirical formula.

 

[RockenNS42]

first try to find the percentage of carbon from CO2 and hydrogen from h20 and sulphur from so2 then calculae percentage of oxygen from it.
now find mole of each element from its percentage .then find its atomic ratio.this would give the value o empirical formula.

thank you very much! I get it know :)