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## Homework Statement

Radius of loop: 20 m

Mass of cart: 225 kg

Gravity: 10 m/s/s (once I figure out how to do this I'll use 9.8 in the final project)

Found so far:

B) Velocity (top of loop) = 14.14 m/s

C) GPE at the top of the loop = 90000 N

C) KE top of loop = 22500 N

D) KE (bot) = 180000 N

## Homework Equations

A) Fg = mg = 225 kg * 10 m/s/s = 2250 N

B) Fg = mv^2/r

C) GPE (top of loop) = KE (top of loop) - heat (lost going through loop)

## The Attempt at a Solution

B) Using these equations I found that the velocity at the top of the loop is 14.14 m/s.

C) 90000 N (GPE = mgh) = 22500 (KE =1/2mv^2) - heat.

That means heat would have to be (-)67500 N. Because of conservation of energy, those three energies added together should be the energy at the bottom (before) the loop. Where all energy would be allocated to KE because height at that point is 0. So

D) KE (bot) = 180000 N

I'm confused as to where to go next. The KE (bot) should be equal to the GPE at the top - whatever heat was lost going down the hill. But how would I find the heat lost there? Would it be the same as before (67500 N)?