How to find sum of the given infinte series

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Homework Help Overview

The discussion revolves around finding the value of the expression ##\sqrt{12+\sqrt{12+\sqrt{12+ ...}}}##, which is presented as an infinite nested radical. Participants are exploring the nature of this expression and its convergence.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants denote the limit of the expression as a variable and attempt to set up equations to solve for it. Others question the classification of the expression, noting it is not an infinite series but rather an infinite nested radical.

Discussion Status

Participants are actively engaging with the problem, with some providing methods to express the problem algebraically. There is acknowledgment of the need to demonstrate convergence, indicating a productive direction in the discussion.

Contextual Notes

There is a mention of confusion regarding the terminology used to describe the expression, as well as the necessity to show that the expression converges.

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Homework Statement


The value of ##\sqrt{12+\sqrt{12+\sqrt{12+ ...}}}## is

Homework Equations

The Attempt at a Solution


No Clue
 
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22990atinesh said:

Homework Statement


The value of ##\sqrt{12+\sqrt{12+\sqrt{12+ ...}}}## is

Homework Equations

The Attempt at a Solution


No Clue

Denote the limit when you do the sum and square root infinite times by A.
##A=\sqrt{12+\sqrt{12+\sqrt{12+ ...}}}##.
If you do the same once more, nothing changes
##A=\sqrt{12+A}##.
Solve for A.
 
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22990atinesh said:

Homework Statement


The value of ##\sqrt{12+\sqrt{12+\sqrt{12+ ...}}}## is

Homework Equations

The Attempt at a Solution


No Clue
Assign the entire sum as a variable.
##\sqrt{12+\sqrt{12+\sqrt{12+ ...}}} = k##
##\Rightarrow 12+\sqrt{12+\sqrt{12+ ...}} = k^2## ... (1)
But,
##\sqrt{12+\sqrt{12+ ...}} = k## ...(2)
Substitute (2) in (1),
Then solve for ##k##.
 
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Ashes Panigrahi said:
Assign the entire sum as a variable.
##\sqrt{12+\sqrt{12+\sqrt{12+ ...}}} = k##
##\Rightarrow 12+\sqrt{12+\sqrt{12+ ...}} = k^2## ... (1)
But,
##\sqrt{12+\sqrt{12+ ...}} = k## ...(2)
Substitute (2) in (1),
Then solve for ##k##.

Thnax got it.
 
22990atinesh said:

Homework Statement


The value of ##\sqrt{12+\sqrt{12+\sqrt{12+ ...}}}## is

Homework Equations

The Attempt at a Solution


No Clue

Others have already shown you how. However, please realize that the above is not an infinite series. It is an infinite "something", just not a series.
 
To be complete you need to show that your expression is convergent.
 

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