Completely expand as a sum/difference of logs

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Homework Help Overview

The problem involves expanding a logarithmic expression into a sum and difference of logs. The expression given is log [ ( 2x^4(x-15)^3) / (12 sqrt (x^4-16) ].

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial attempts to apply logarithmic properties, such as the quotient rule and product rule. There is a focus on ensuring clarity in notation and the correct application of logarithmic identities.

Discussion Status

Some participants are questioning the clarity of the original expression and the notation used. Others are exploring how to properly apply logarithmic properties to expand the expression fully. There is a recognition that further steps are needed to achieve complete expansion.

Contextual Notes

There are mentions of potential misunderstandings regarding the use of parentheses and the representation of exponents. Participants are also noting the importance of clarity in mathematical expressions to avoid confusion.

lolilovepie
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Homework Statement



Completely expand as a sum/difference of logs
log [ ( 2x^4(x-15)^3) / (12 sqrt (x^4-16) ]

Homework Equations


The Attempt at a Solution



log 2x^4(x-15)^3 - log 12 sqrt (x^4-16)
3 log 2x^4(x-15) - 1/2log 12 (x^4-16)
 
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lolilovepie said:

Homework Statement



Completely expand as a sum/difference of logs
log [ ( 2x^4(x-15)^3) / (12 sqrt (x^4-16) ]
Some clarification, please. The numerator of what you wrote is
2x4 * (x - 15)3.

If that isn't what you meant, please use parentheses or brackets to make it clearer.
lolilovepie said:

Homework Equations





The Attempt at a Solution



log 2x^4(x-15)^3 - log 12 sqrt (x^4-16)
3 log 2x^4(x-15) - 1/3log 12 (x^4-16)

Some parentheses would make this more readable, as would the inclusion of = for things that are equal.

Also, sqrt(x) = x1/2, not x1/3.
 
Mark44 said:
Some clarification, please. The numerator of what you wrote is
2x4 * (x - 15)3.

If that isn't what you meant, please use parentheses or brackets to make it clearer.


Some parentheses would make this more readable, as would the inclusion of = for things that are equal.

Also, sqrt(x) = x1/2, not x1/3.

1) yeah, that's what i meant to say, but i didn't know how to do the exponents

2) ok okay thanks! did I solve the problem right because I'm not very sure :\
 
Starting here --
log [ ( 2x^4 * (x-15)^3) / (12 sqrt (x^4-16) ]
= log [ 2x^4 * (x-15)^3] - log[12 * (x^4-16)^(1/2)]
Can you continue?

Notice that I added * to indicate multiplication. I think that's what you intended, but am not sure.

There are some properties of logs that you either don't know or aren't using, such as log(AB) = log(A) + log(B), assuming both A and B are positive.
 
Mark44 said:
Starting here --
log [ ( 2x^4 * (x-15)^3) / (12 sqrt (x^4-16) ]
= log [ 2x^4 * (x-15)^3] - log[12 * (x^4-16)^(1/2)]
Can you continue?

Notice that I added * to indicate multiplication. I think that's what you intended, but am not sure.

There are some properties of logs that you either don't know or aren't using, such as log(AB) = log(A) + log(B), assuming both A and B are positive.

after continuing would it be:

[log 2x^4 + log (x-15)^3] - [log 12 + log (x^4-16)^1/2]

and then use the power rule?

[4 log 2x + 3 log (x-15)] - [log 12 + 1/2 log (x^4-16)]
 
lolilovepie said:
after continuing would it be:

[log 2x^4 + log (x-15)^3] - [log 12 + log (x^4-16)^1/2]

and then use the power rule?

[4 log 2x + 3 log (x-15)] - [log 12 + 1/2 log (x^4-16)]

It's still not completely expanded.
 

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