How to find tension in strings pulling on carts.

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Homework Help Overview

The problem involves three carts connected by strings, with a force applied to the first cart. Participants are tasked with determining the acceleration of the system and the tension in the strings connecting the carts. The subject area includes dynamics and tension in strings.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the importance of free body diagrams (FBD) for each cart and explore how to apply Newton's second law to find the tension forces. There is confusion regarding the calculation of tension magnitudes and the net forces acting on the carts.

Discussion Status

Some participants have provided guidance on using FBDs and applying the net force equation. The discussion is ongoing, with various interpretations of how to approach the tension calculations being explored.

Contextual Notes

Participants note the necessity of illustrating answers with free body diagrams and express uncertainty about the equations needed to find tension. There is a focus on understanding the forces acting on each cart in the system.

drunkenrobot
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Homework Statement



3 carts are connected by strings. The first cart is 5kg, the second 2kg, and the third 8kg. A string is fixed at the front of the first cart is pulled with a force of 30 N. In the following problems be sure to illustrate your answers with the corresponding free body diagrams.

a. What is the acceleration of the train of carts?

b. What is the tension in the string connecting the first and second car?

c. What is the tension in the string connecting the second and third car?


Homework Equations



Fnet = ma

I don't remember the equations to find tension

The Attempt at a Solution



I figured out the acceleration easily:

Fnet = (m1 + m2 + m3)a
30 N = (15kg)a
a = 2 m/s ^2

The problem I'm having is I forget how to find the tension force in the strings.

Any help?
 
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Drawing a FBD for each cart is THE FIRST STEP and is VERY IMPORTANT.
 
ok, so for the first one I have 30 N pulling it in one direction (let's say to the left). So then the tension Force (Ft) is pulling in the opposite direction, right? But this is where I get confused. I don't know how to find the magnitude of the tension force.
 
Try to use Fnet = ma for the FIRST cart.
 
so I have a force of 10 N pulling to the left?
 
Considering the first cart:

Let us keep the FBD in mind.

The first cart has 30N to the left and the tension T to the right. Hence Fnet in the direction of the acceleration is (30 - T).

using Fnet = ma (in the direction of the acceleration)
30 - T = 5 x 2

etc.

The same may be done for the other two carts. Always keep the FBD in mind.
 

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