How to find the exact value of cos 67.5 ?

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Homework Help Overview

The discussion revolves around finding the exact value of cos(67.5) in the context of a precalculus homework problem. Participants explore trigonometric identities and simplifications related to angles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find cos(67.5) by considering it as a half-angle of 135 degrees but gets stuck in the simplification process. Other participants question the relationship between cos(x) and cos(x+90) and suggest various algebraic manipulations to simplify the expression.

Discussion Status

Participants are actively engaging with the problem, offering suggestions and exploring different approaches. Some guidance has been provided regarding squaring the formula and simplifying, but there is no explicit consensus on the best method yet.

Contextual Notes

The original poster expresses difficulty in simplifying their initial approach, indicating a potential gap in understanding the half-angle identity and its application. There is also mention of a square root that complicates the simplification process.

jkristia
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One of the questions in the homework for online precalc class I'm taking is to find the exact value for cos (67.5).
At first I didn't realize that I should just take the half angle of 135, so instead I tried to find the value for cos (45 + 45/2), and got stuck at this point.

attachment.php?attachmentid=44118&stc=1&d=1329679233.png


If I calculate the actual value I get the correct answer, but I'm not able to see how I can simplify this further.
I know the solution is as simple as finding the half angle value of

attachment.php?attachmentid=44119&stc=1&d=1329679233.png


Any suggestions of how I can get from my first attempt solution to the simpler (and correct) solution?
 

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How is Cos(x) related to Cos(x+90), how is Cos(x+90) related to other trig functions?
 
Try multiplying both the top and bottom by ##\sqrt{2-\sqrt{2}}##.
 
>>How is Cos(x) related to Cos(x+90), how
yeah, that definitely makes it simpler

attachment.php?attachmentid=44137&stc=1&d=1329699522.png


>>Try multiplying both the top and bottom by
I have tried, but I seem to end up with a square root I can't get rid of, but I will keep trying.


Thanks for your help
Jesper
 

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Hi, jkristia,

Square your formula for cos(45+45/2), simplify, and then take the square root.ehild
 
ehild said:
Hi, jkristia,

Square your formula for cos(45+45/2), simplify, and then take the square root.


ehild

ah - of course, that works
Thank you very much
 

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