How to find the Jordan Canonical Form of a 5x5 matrix and its steps?

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SUMMARY

The discussion focuses on the process of finding the Jordan Canonical Form of a 5x5 matrix, specifically the matrix \(\begin{pmatrix}177& 548& 271& -548& -356\\ 19& 63& 14& -79& -23\\ 8& 24& 17& -20& -20\\ 42& 132& 55& -141& -76\\ 56& 176& 80& -184& -105\end{pmatrix}\). Key steps include determining the eigenvalues and their multiplicities, as well as finding the corresponding eigenvectors and generalized eigenvectors. The Jordan normal form derived from the provided eigenvalue table is \(\begin{pmatrix}3&1&0&0&0\\0&3&0&0&0\\0&0&3&1&0\\0&0&0&3&0\\0&0&0&0&-1\end{pmatrix}\).

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors
  • Familiarity with Jordan Canonical Form
  • Matrix multiplication techniques
  • Knowledge of generalized eigenvectors
NEXT STEPS
  • Study the process of finding eigenvectors for multiple eigenvalues
  • Learn about constructing transition matrices in linear algebra
  • Explore the implications of Jordan normal forms in systems of differential equations
  • Investigate the relationship between eigenvalues, algebraic multiplicity, and geometric multiplicity
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Students and professionals in mathematics, particularly those studying linear algebra, matrix theory, and anyone working with systems that require the analysis of matrix transformations.

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To see the steps I have completed so far, https://math.stackexchange.com/q/3168898/261956

I think there are at least three more steps. The next step is finding the eigenvectors together with the generalized eigenvectors of each eigenvalue. Then we use this to construct the transition matrix. Then we do matrix multiplication in order to
 
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If you already have the eigenvalues of
\begin{pmatrix}177& 548& 271& -548& -356\\ 19& 63& 14& -79& -23\\ 8& 24& 17& -20& -20\\ 42& 132& 55& -141& -76\\ 56& 176& 80& -184& -105\end{pmatrix}

with their multiplicity, then I read from your table
\begin{array}{c|c|c}
\lambda & \operatorname{am}_C(\lambda) & \operatorname{gm}_C(\lambda) \\ \hline
3 & 4 & 2 \\
-1 & 1 & 1
\end{array}
the Jordan normal form ##\begin{pmatrix}3&1&0&0&0\\0&3&0&0&0\\0&0&3&1&0\\0&0&0&3&0\\0&0&0&0&-1\end{pmatrix}##

Given the informations are correct, what do you want to know?
 

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