How to find the Location of the point P

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SUMMARY

The discussion focuses on determining the location of point P, which is positioned 3 cm from line AB and 5 cm from point A. Participants suggest using a compass to draw a circle with a 5 cm radius centered at point A to identify potential locations for point P. The intersection of this circle with line CD indicates one possible location for point P, while acknowledging that there are additional locations on the opposite side of line AB and along a line parallel to AB. Ultimately, there are four possible locations for point P based on the given constraints.

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A portion of a sketch drawn by a student to obtain the location of a point P which lies at a distance of 3cm from the given straight line AB and 5cm from the point A, is shown in the figure. Complete the sketch and mark the location of the point P.

View attachment 5966

point P which lies at a distance of 3cm from the given straight line AB

This is is already included.

And the point P lies 5 cm away from point A, This should mean the diagonal length from the point A to the point P should be 5cm.

So, Any Ideas on the location of point 'P'. (Smile)
 

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mathlearn said:
A portion of a sketch drawn by a student to obtain the location of a point P which lies at a distance of 3cm from the given straight line AB and 5cm from the point A, is shown in the figure. Complete the sketch and mark the location of the point P.

This is is already included.

And the point P lies 5 cm away from P , So any Ideas on the location of point 'P'. (Smile)

Take a look at my avatar and find x? ;)

Alternatively, use a compass to draw a circle with radius 5 cm and A at its center.
 
I like Serena said:
Take a look at my avatar and find x? ;)

(Smile) (Giggle) Here It Is
I like Serena said:
Alternatively, use a compass to draw a circle with radius 5 cm and A at its center.

Hmm.. The intersection point of the arc from the point A with radius 5 cm on the line CD would be point P then?
 
mathlearn said:
(Smile) (Giggle) Here It Is

Hmm.. The intersection point of the arc from the point A with radius 5 cm on the line CD would be point P then?

Yep. (Nod)
 
I like Serena said:
Yep. (Nod)

Thank you so much ! (Smile)
 
Of course there are two other possible locations of $P$ on the other side of $AB$…
 
Evgeny.Makarov said:
Of course there are two other possible locations of $P$ on the other side of $AB$…

And if we extend the line CD there can be another location too!

So there can be four possible location for P two on CD & the other would be on a line 3 cm away & parallel to AB.

View attachment 6055

Many Thanks :)
 

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