How to Find the Magnetic Field Gradient from Four Parallel Wires?

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SUMMARY

The discussion focuses on calculating the magnetic field gradient (\(\tilde B\)) generated by four parallel wires carrying current \(I\). The key equation referenced is derived from Maxwell's equations, specifically \(\frac{dB_x}{dx} = -\frac{dB_y}{dy} \equiv \tilde B\). The user seeks a method to express \(\tilde B\) in terms of the current \(I\) and the finite length \(L\) of the wires. The conversation highlights the importance of visual aids, as the initial absence of a figure hindered understanding.

PREREQUISITES
  • Understanding of Maxwell's equations
  • Knowledge of magnetic field concepts
  • Familiarity with vector calculus
  • Basic principles of electromagnetism
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  • Research the application of Maxwell's equations in calculating magnetic fields
  • Study the Biot-Savart Law for magnetic field calculations
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Niles
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Homework Statement


Hi

I am looking at four parallel wires of finite length L, whose currents run in the directions shown in the attached figure. There is no gradient along the wire-axis, so from Maxwell's equation
[tex] \frac{dB_x}{dx} = -\frac{dB_y}{dy} \equiv \tilde B.[/tex]
How would I go about finding an expression for the gradient [itex]\tilde B[/itex] given some current I though the wires? This isn't a homework question, I have just not been able to find the answer anywhere.


Niles.
 

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Niles said:

Homework Statement


Hi

I am looking at four parallel wires of finite length L, whose currents run in the directions shown in the attached figure. There is no gradient along the wire-axis, so from Maxwell's equation
[tex] \frac{dB_x}{dx} = -\frac{dB_y}{dy} \equiv \tilde B.[/tex]
How would I go about finding an expression for the gradient [itex]\tilde B[/itex] given some current I though the wires? This isn't a homework question, I have just not been able to find the answer anywhere.


Niles.

I'm not seeing the figure...?
 
Sorry, I'll upload it in just a few minutes. Thanks for letting me know.

EDIT: I have attached it now. Thanks.
 

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