How to find the number of unpaired electrons?

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SUMMARY

The discussion focuses on determining the number of unpaired electrons in compounds such as aluminum sulfate (Al2(SO4)3) and ferrous sulfate (FeSO4). It establishes that the presence of unpaired electrons is crucial for assessing paramagnetism. The participants emphasize the importance of writing electron configurations and constructing orbital diagrams for ions like Al3+ and Fe2+ to visualize electron arrangements effectively.

PREREQUISITES
  • Understanding of electron configurations
  • Knowledge of orbital diagrams
  • Familiarity with paramagnetism and diamagnetism
  • Basic chemistry concepts related to cations and anions
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  • Study the electron configuration of aluminum ions (Al3+) and iron ions (Fe2+)
  • Learn how to construct and interpret orbital diagrams for transition metals
  • Research the principles of paramagnetism and diamagnetism
  • Explore the properties of common anionic and cationic species in chemistry
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Chemistry students, educators, and professionals interested in understanding electron configurations and their implications for magnetic properties of compounds.

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How do you find the number of unpaired electrons in a salt such as aluminum sulphate or ferrous sulphate. The number of unpaired of electron or bond order is needed to determine if something is paramagnetic.
 
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Most anionic species and cationic species (amines, non-transition metals) have all paired electrons, like you asked, sulphate have no unpaired electron.

To find out unpaired electron in metals, you must write its configuration. Try writing the configuration of Al3+ and Fe2+, even try drawing orbital diagram of last orbital/last 2 orbitals to get a better picture.
 

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