How to find the orientation of polarization of a polarizer

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Discussion Overview

The discussion revolves around methods to determine the orientation of polarization of a linear polarizer when no markings indicate the angle. Participants explore various techniques and sources of polarized light, including reflections and known polarizers.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests using a known linear polarizer in series or a polarized light source, such as the sky or reflections, to determine the orientation.
  • Another participant mentions that LCD screens can serve as a source of polarized light, noting their orientation may align with the polarization needed for viewing through polarized sunglasses.
  • A participant questions the use of a quarter wave plate with a known fast axis to find the orientation of an unknown polarizer, expressing uncertainty about its application.
  • One participant observes that the polarization of their LCD display is at 45 degrees and suggests using reflections from a shiny floor to find the vertical orientation of the polarizer.
  • Another participant shares an experience with a film used to repair an LCD, noting that the polarization axis was offset by 45 degrees and that reflections from water helped determine the axis.
  • A suggestion is made to use a phone screen as a polarized light source, with the assumption that its polarization aligns with the longer side of the device.
  • One participant proposes checking oblique reflections from a clean sheet of glass to find the nulls for light, suggesting that the true polarization corresponds to the bisector between the two results.

Areas of Agreement / Disagreement

Participants present multiple competing methods and observations without reaching a consensus on the best approach to determine the orientation of polarization.

Contextual Notes

Some methods rely on specific conditions, such as the angle of reflections or the characteristics of the light source, which may not be universally applicable.

boxfullofvacuumtubes
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If you have a new linear polarizer, how do you find its orientation of polarization? In other words, how do you orient it so it would, let say, polarize light vertically if there is no marking for the 0 degrees angle?
 
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The easiest way would be using a known linear polariser and place them in series or use a known polarised source of light such as the sky or an angled reflection.

Edit: Or the light from an LCD screen. A few years back I noted in delight that all LCDs in the bus stations where I lived had the correct polarisation orientation to be seen with polarised sunglasses (which are always oriented the same way to reduce reflections on horizontal surfaces) assuming you keep your head vertical. Whether by happy coincidence or intelligent design I cannot say.
 
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If I don't have another known linear polarizer to check the orientation against, is there any way to use a quarter wave plate with a known fast axis for this purpose? I just can't think of any, but smart people around here might.

Orodruin, I like your idea to use an LCD screen as a source of light with known polarization.
 
The polarization of one of the LCD displays I have here is oriented at 45 degrees relative to the edges.
But you can always look at the light reflected by a shiny floor, at some angle. The reflected light is partially polarized parallel to the floor.
When the floor looks the darkest through the polarizer the direction of the polarizer is vertical (perpendicular to the floor).
 
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I recently made the same observation as mentioned in the thread "Flipping a polarizer 180deg. changes polarization" with some film I purchased on ebay to repair the LCD displays on my tractor's instrument cluster.
I eventually realized that the polarization axis is offset by 45°. Flipping the film about its H or V axis is equivalent to rotating by 90°.
I determined the film's polarization axis by noting the effect of viewing reflections from water surfaces.
 
boxfullofvacuumtubes said:
Orodruin, I like your idea to use an LCD screen as a source of light with known polarization.
Have you tried your phone screen? If it's polarized then it's along the longer side.
 
In the absence of anything else, you can look at oblique reflections of a clean sheet of glass.
If you have a simple polariser with unknown polarisation plane, you could check results by finding nulls for light in both directions.
As far as I can make out, the 'true' polarisation will correspond to the bisector between the two results.
 
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