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How to Find the Resultant Vector of this Quadrilateral ?

  1. Apr 17, 2010 #1
    This question is from a "Solved Problems" book where they give the solutions but I'm not able to get the reason !

    Question :

    ABCD is a quadrilateral.Force BA,BC,CD and DA act at a point.Their resultant is :

    f0n59e.jpg

    Options:

    a. 2AB
    b. 2DA
    c. 2BC
    d. 2BA

    The given answer is : 2BA

    Formulas Related

    Polygonal Laws of vector which states that the resultant will be the Line joining the Initial point and the final point !

    My Attempt:

    How is this possible.I'm not able to understand how we should find the resultant of the Quadrilateral because AB is not joining "Head to Tail" and "Tail to Head" instead it is joining from "Tail to Tail" and "Head to Head" ! So how do i solve this please give a proper explaination for this !

    What i think is that only "AB" is the answer because When we join the initial point "B" with the final point "D" we should get the resultant ! So how do we do this ?

    Please help me Understand this ! Am i mixing up the concepts or what ?
     
    Last edited: Apr 17, 2010
  2. jcsd
  3. Apr 17, 2010 #2

    ehild

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    As the vectors AB, BC, CD, DA form a quadrilateral, their resultant is zero. AB + BC + CD + DA = 0. The vectors AB and BA are opposite: AB =-BA, so BA = BC + CD + DA.

    You have to determine the resultant force Fr= BA + BC + CD + DA. The last three add up to BA.

    ehild
     
  4. Apr 17, 2010 #3
    But how can you take that AB+BC+CD+DA = 0 Because AB is an exception it is not Joining "Head to Tail" and "Tail to Head" instead it is joining "Tail to Tail" and "Head to "Head".So how can we tell that

    Only when AB is joined "Head to Tail" and "Tail to Head" only then we can tell the resultant is 0 !

    And how can you add them up to find the resultant force..We need to find the resultant vector only that will be the resultant force right ?

    Please explain about my question !
     
  5. Apr 20, 2010 #4
    Bump.............................
     
  6. Apr 20, 2010 #5

    tiny-tim

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    Hi 5416339! :smile:

    Suppose the arrow on AB was reversed, what would be resultant be then?

    Now what's the difference between the forces given, and the forces with the arrow on AB reversed? :wink:
     
  7. Apr 20, 2010 #6

    ehild

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    I explained your question in the previous post. I thought you know how to add vectors with the polygon method. Well, again: The first letter means tail, the second letter is the head of a vector. See your picture: The vector BA (head at A and tail at B) is the vector sum of BC+CD+CA=BA. So BA+BC+CD+DA= BA+(BC+CD+DA) = BA +BA=2BA

    By the way, if you consider the sides of a polygon as vectors, all joining with head to tail, then the sum of this vectors is zero. If you reverse the direction of the vector BA (it becomes AB, and AB=-BA) all vectors will join with head to tail and their sum is zero, as it is a closed polygon: AB+BC+CD+DA=0 --->-AB = BA = BC+CD+DA.

    ehild
     
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