I understand perfectly well how to do Taylor series, but I am foggy on these Laurent series. Say, we have something like,(adsbygoogle = window.adsbygoogle || []).push({});

[tex]f\left( z \right)\; =\; \frac{1}{z^{2}\cdot \sin \left( z \right)}[/tex]

I think I need to use the taylor series expressions for sin(z) but otherwise, I am not sure what to do about that z^2. If I use that in a taylor series with z=0, then I get a singularity.

Since its 1/sin(z), do I just inverse the taylor series for sin(z) Yes, you can see I am very unknowledgeable about this. I turn here because the explanations I found in my book are totally lacking.

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# How to find this Laurent series?

Loading...

Similar Threads for find Laurent series | Date |
---|---|

I Can i find this integral in a simpler way | Jan 14, 2018 |

I Q about finding area with double/volume with triple integral | Sep 13, 2017 |

I Finding a unit normal to a surface | Sep 13, 2017 |

I Finding value of parameters to fit some data | Sep 11, 2017 |

Clarifications regarding definitions of Taylor, Laurent etc. series | Feb 16, 2014 |

**Physics Forums - The Fusion of Science and Community**