- #1

itzernie

- 23

- 4

## Homework Statement

The circuit of the given problem is attached to this post (jpg file). All info is given in the photo.

Problem: find V

_{A}, V

_{B}, I

_{A}.

## Homework Equations

Ohms law

KCL equations

P = VI or V^2/R

## The Attempt at a Solution

**-**First, I noted that V

_{B}= 9 - V

_{A}.

- next, i set up a KCL equation at V

_{A}:

-.004V

_{B}+ V

_{A}/30 + (2V

_{A}-18)/30 = 0

- i plugged in V

_{B}:

-.004(9-V

_{A}) + V

_{A}/30 + (2V

_{A}-18)/30 = 0

- Solved for V

_{A}= 6.115 V

- Therefore V

_{B}must = 2.885 V (given everything so far is correct

- by Ohm's law, I

_{A}= V

_{B}/ 15 k ohms

- I

_{A}= 0.1923 mA

- so at this point I have values for all i need to solve the problem, but to check if i was right I wanted to check consv of power.

- KCL at V

_{A}node = .1923 + 11.54 = I

_{B}

I

_{B}= 11.7323 mA

When I checked the power on all 4 items in this circuit, the power did not check out to zero, so somewhere I messed up but I have no idea where.