ytpj Messages 2 Reaction score 0 Thread starter Feb 10, 2008 #1 Homework Statement [tex]\frac{2-x}{2+x}=t^3[/tex] How to find x? Answer is [tex]x=\frac{2-2t^3}{1+t^3}[/tex]
Homework Statement [tex]\frac{2-x}{2+x}=t^3[/tex] How to find x? Answer is [tex]x=\frac{2-2t^3}{1+t^3}[/tex]
quasar987 Science Advisor Homework Helper Gold Member Messages 4,796 Reaction score 32 Feb 10, 2008 #2 Start by multiplying both sides of the equation by (x+2).
CompuChip Science Advisor Homework Helper Messages 4,305 Reaction score 49 Feb 10, 2008 #3 ytpj said: [tex]\frac{2-x}{2+x}=t^3[/tex] How to find x? Reminds me of this very old one (but seriously, do what quasar987 told you)
ytpj said: [tex]\frac{2-x}{2+x}=t^3[/tex] How to find x? Reminds me of this very old one (but seriously, do what quasar987 told you)
ytpj Messages 2 Reaction score 0 Feb 10, 2008 #4 I don't understand where this leading. It still will be [tex]2-x=2t^3+xt^3[/tex] so what?
quasar987 Science Advisor Homework Helper Gold Member Messages 4,796 Reaction score 32 Feb 10, 2008 #5 Then send everything on the same side of the equation so that you get [tex]2-x-2t^3+xt^3=0[/tex] and factor the x.
Then send everything on the same side of the equation so that you get [tex]2-x-2t^3+xt^3=0[/tex] and factor the x.