- #1
ytpj
- 2
- 0
Homework Statement
\frac{2-x}{2+x}=t^3
How to find x?
Answer is
x=\frac{2-2t^3}{1+t^3}
How to Find X in a Quadratic Equation?
- Thread starter ytpj
- Start date
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Homework Help Overview
The problem involves solving for x in the equation \(\frac{2-x}{2+x}=t^3\), which falls under the subject area of algebra, specifically quadratic equations.
Discussion Character
- Exploratory, Problem interpretation, Assumption checking
Approaches and Questions Raised
- Participants discuss various methods to manipulate the equation, including multiplying both sides by (x+2) and rearranging terms. Some express confusion about the direction of the solution and the implications of rearranging the equation.
Discussion Status
The discussion is ongoing, with participants offering different approaches to rearranging the equation. There is no explicit consensus on the best method, but some guidance has been provided regarding moving terms to one side of the equation.
Contextual Notes
Participants are navigating the implications of their manipulations and questioning the clarity of the steps involved in solving the equation. There is an indication of varying levels of understanding among the participants.
\frac{2-x}{2+x}=t^3
How to find x?
Answer is
x=\frac{2-2t^3}{1+t^3}
- #2
quasar987
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Start by multiplying both sides of the equation by (x+2).
- #3
CompuChip
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- #4
ytpj
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I don't understand where this leading. It still will be
2-x=2t^3+xt^3 so what?
2-x=2t^3+xt^3 so what?
- #5
quasar987
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Then send everything on the same side of the equation so that you get
2-x-2t^3+xt^3=0
and factor the x.
2-x-2t^3+xt^3=0
and factor the x.
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