How to generalize a theorem to 3D

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SUMMARY

The discussion focuses on generalizing a theorem related to Fourier transforms and Hilbert spaces from R2 to R3. The original theorem establishes bounds for norms of functions and their transforms in a Hilbert scale, specifically stating that ||f||_H(R2) <= ||RF||_H(Z) where Z is a cylinder. The goal is to extend this result to three dimensions, resulting in the inequality ||f||_H(R3) <= ||Rf||_H(Z) with Z as a sphere. Participants confirm that generalization involves adapting the proof from the 2D case to derive the 3D equations.

PREREQUISITES
  • Understanding of Fourier transforms in Hilbert spaces
  • Knowledge of norm bounds in functional analysis
  • Familiarity with mathematical proofs and generalization techniques
  • Concept of dimensionality in mathematical contexts (R2, R3)
NEXT STEPS
  • Study the properties of Hilbert spaces in R3
  • Learn about Fourier transforms in higher dimensions
  • Explore generalization techniques in mathematical proofs
  • Investigate norm inequalities in functional analysis
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Mathematicians, students of advanced calculus, and anyone involved in functional analysis or theoretical physics will benefit from this discussion.

balugaa
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Homework Statement



So have this theorem defined for transforms on the Fourier kind, and hilbert spaces, on R2
The theorem sets bounds for norms of the functions and the transforms in the hilbert scale

I have the proofs for the 2D case given in my lecture notes

Problem: Generalize the above 2D theorem to prove a 3D result.

what does generalize the theorem mean?

Homework Equations



||f||_H(R2) <= ||RF||_H(Z) - here Z = cylinder



The Attempt at a Solution



So i have to use the generalisation to show

||f||_H(R3) <= ||Rf||_H(Z) - here Z = sphere

Does generalize mean i basically take the proof on the theorem above, and plug in the 3D case in the proof to derive the equations?

Basically this is what i would have done, just wanted to check that that's what generalize a theorem mean
 
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generalise often means to extend or make the theorem applicable to less restrictve conditions, in this case showing the R^2 result can be extended to R3
 
lanedance said:
generalise often means to extend or make the theorem applicable to less restrictve conditions, in this case showing the R^2 result can be extended to R3

Cool, i went all the way to R^n with the orig theorem, worked through the proof plugged in n=2 to show the 2D result .. and n = 3 for the 3D ...
 

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