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Quick question:
h(x) = sinx/cos^(2) x
= (1/cosx)(sinx/cosx)
Then you get (secx)(tanx)..
I do not get how they get secx x tanx?? Anyone?? Thanks
h(x) = sinx/cos^(2) x
= (1/cosx)(sinx/cosx)
Then you get (secx)(tanx)..
I do not get how they get secx x tanx?? Anyone?? Thanks