How to get the Nyquist Rate if there is two given samples.

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SUMMARY

The discussion centers on determining the Nyquist Rate for the signal defined by the equation x(T) = 2sin(2000πT) + 3cos(6000πT). The Nyquist Rate is established as twice the highest frequency present in the signal, which in this case is 6000 Hz, leading to a Nyquist Rate of 12000 Hz. The conversation emphasizes the importance of identifying the bandwidth of the signal to accurately calculate the Nyquist Rate, as defined in signal processing principles.

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Example is x(T) = 2sin(2000piT)+3cos(6000piT)
there will be two nyquist rate?
 
Calgenometry said:
Example is x(T) = 2sin(2000piT)+3cos(6000piT)
there will be two nyquist rate?
From wikipedia: "In signal processing, the Nyquist rate, named after Harry Nyquist, is twice the bandwidth of a bandlimited function or a bandlimited channel."
So what is here the band limit?
 

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