How to get tis relation any hints:

[sphyics]

please help me :) to get tis relation.

 

[Doc Al]

Assuming those vectors add to zero, just add the horizontal components.

 

[sphyics]

Assuming those vectors add to zero, just add the horizontal components.

still not clear

 

[Doc Al]

still not clear

Do you have a specific question? Where did this relationship come from? I assume it's part of a larger problem?

Do you know how to find components of a vector? Read this: http://hyperphysics.phy-astr.gsu.edu/HBASE/vect.html#vec5"

 

[HallsofIvy]

The statement $T_1= T_2+ T3cos(\theta)$ is only true if, "T₁", "T₂", and "T₃" are the lengths of the vectors shown and the horizontal components sum to 0. (If both T₁ and T₂ are horizontal and T₃ isn't, as shown, the vectors them selves cannot sum to 0.)

Since T₁ and T₂ are both horizontal, you need to look at the horizontal component of T₃. Drop a perpendicular from the tip of T₃ to the horizontal. You get a right triangle with angle $\theta$ and hypotenuse of length T₃. The horizontal component of T₃, T_{x then satisifies $cos(\theta)= T_x/T_3$ so $T_x= T_3 cos(\theta)$.}

 

[sphyics]

horizontal components sum to 0.

yes u r right, i was solving a problem on surface tension. For the equilibrium of the drop, the horizontal components must balance each other.

 

[sphyics]

Do you have a specific question? Where did this relationship come from? I assume it's part of a larger problem?

yes, its a part of a larger problem; problem on surface tension.

Do you know how to find components of a vector? Read this: http://hyperphysics.phy-astr.gsu.edu/HBASE/vect.html#vec5"

yes i know to find components, BTW i appreciate ur help u always replies to my posts; thanks for ur valuable time

 

[HallsofIvy]

yes, its a part of a larger problem; problem on surface tension.



yes i know to find components, BTW i appreciate ur help u always replies to my posts; thanks for ur valuable time

Doc Al's point was "Apply that method (of finding components) and you will answer your own question!"