How to get Voltage vs. Time graph from having Current and Voltage values.

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SUMMARY

The discussion focuses on generating a Voltage vs. Time graph using known Resistance, Voltage, and Current values in an RC circuit setup. The equation V(t) = V(0)*e^-(t/rc) is central to the analysis, where 'rc' represents the time constant derived from Resistance and Capacitance. Participants clarify that in a series circuit with three light bulbs, capacitance is negligible, leading to confusion about the application of the time constant. The discussion emphasizes the importance of accurate voltage measurements using a multimeter rather than relying on the power supply readout.

PREREQUISITES
  • Understanding of Ohm's Law and its application in circuits
  • Familiarity with RC circuit theory and time constants
  • Experience with data collection using multimeters
  • Proficiency in using curve plotting software like Logger Pro or MATLAB
NEXT STEPS
  • Learn how to accurately measure voltage and current in series circuits using multimeters
  • Explore the use of Logger Pro for plotting current-voltage curves
  • Study the concept of differential resistance and its calculation from current-voltage data
  • Investigate the implications of nonlinearity in current-voltage relationships in resistive components
USEFUL FOR

This discussion is beneficial for physics students, electrical engineering students, and educators involved in circuit analysis and experimental design, particularly those focusing on RC circuits and data analysis techniques.

suntrix
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Homework Statement



Make a Voltage vs. Time graph. We know the Resistance, Voltage values, and corresponding Current Values.

Homework Equations



We have data points for the voltage, which ranges from 0-10 volts, and we have the corresponding current values.

V(t) = V(0)*e^-(t/rc)

The Attempt at a Solution



I was looking at equations that might help me solve this problem.

I know that V(t) = V(0)*e^-(t/rc)

rc is the time constant. But isn't RC the Resistance x the Capacitance. We had three light bulbs connected in series, so there was no capacitance. And I already solved for the resistance.

I'm just confused. Help please.
----------------------------------

If you're confused with the setup, here is the whole unedited problem.!In the following: BECAUSE OF THE POTENTIAL FOR SHOCK OR DAMAGE TO THE
ELECTRONIC INSTRUMENTS, YOU MUST ASSEMBLE YOUR CIRCUIT WITH ALL
MULTIMETERS AND POWER SUPPLY TURNED OFF.
! THE TA WILL INSPECT YOUR CIRCUIT, AND THE TA WILL THEN TURN ON THE
POWER SUPPLY AND MULTIMETERS.
B. Keeping in mind the important
caveats above, assemble your
components as indicated in the
figure. This arrangement
should allow you to measure
the current-voltage curve for
three light bulbs in series. You
should take data points starting
from about 10 Volts down to 0
Volts. Do not exceed 10 Volts
output from the power
supply. Since the voltage
readout on the power supply is very crude it is important to record the voltage as
measured by Multimeter #1 rather than using the power supply readout. Multimeter #2
is placed between the two light bulbs and will be set to measure current; you should use
the 200 mA maximum setting for current measurement. Record a total of 20 – 30 data
points, about 2 for each unit of voltage, and be sure to take at least four points in the
range 0.10 – 1.00 Volts.
Questions
1. Use Logger Pro or some other curve plotting program to plot the current-voltage
behavior for the three light bulbs. Note any nonlinearities in your plot. What is the
source of this nonlinearity? Is it really a breakdown of Ohm’s law?
2. Fit a smooth curve to your current-voltage data using the Logger Pro fitting function or
Matlab. From this data extract the slope of the current-voltage curve when voltage is
near zero. Compare this “differential” resistance with the result of your resistance
measurement from part A for the three light bulbs. Are the two values similar?
3. Include your plot of voltage versus time for the RC circuit.
 
Last edited:
Physics news on Phys.org
The lab description indicates that they want a current-voltage curve, not voltage-time nor current-time. There's no timekeeping involved in the lab!
 

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