How to Graph Moment of Inertia and Frictional Torque?

[cam borrett]

Homework Statement

The moment of inertia (I) of the bicycle wheel about the axle, can be obtained graphically using the equation:
rm(g-a) = I(a/r)+Frictional Torque. Explain how to form two variables so that, I and Frictional Torque can be obtained from a linear graph. Identify the constants corresponding to the slope and intercept of the proposed linear graph.

r = 0.018m
m=0.200kg
g=9.8m/s^2
a=0.002812
I=?
Frictional Torque= ?

Homework Equations

(1) rm(g-a) = I(a/r)+Frictional Torque.

(2) y=mx+b

3. The Attempt at a Solution

Im not sure if I am 100% right on this but, equation one could take the form of equation two.
m being I.
x being what's changing, ie. acceleration
b being the y intercept, ie frictional torque

Just unsure where to go from there a how to graph it.

 

[haruspex]

rm(g-a) = I(a/r)+Frictional Torque.

Presumably these variable relate to a physical set-up of some kind. Please describe it.

 

[andrevdh]

The two variables are m and a. Try and rewrite the equation so that they become the x and y variables in the linear equation (or a combination of the variables!). The frictional torque and moment of inertia should then part of gradient and y-intercept values (r and g will also appear in these).