How to integrate by parts when del operator is involved?

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The discussion centers on integrating a specific expression involving the del operator and electric field, seeking to apply integration by parts correctly. The user is unsure how to identify the appropriate functions for 'u' and 'dv' in the integration process. Respondents emphasize the importance of following the integration by parts formula, providing a variation that incorporates the del operator. They encourage the user to attempt the integration themselves to clarify their understanding. The conversation highlights the need for a clear application of mathematical principles when dealing with vector calculus.
iScience
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i'm trying to integrate this:

$$W=\frac{ε}{2}\int{\vec{∇}\cdot\vec{E})Vdτ}$$

where ε is a constant, E= -∇V, τ is a volume element

how do i end up with the following via integration by parts?

$$W=\frac{ε}{2}[-\int{\vec{E}\cdot(\vec{∇}V)dτ}+\oint{V\vec{E}\cdot d\vec{a}}$$]

where the vector a is an area element

thanks
 
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I know the formula for integration by parts, i don't know what to do with the del operator.

ie, I don't know what to make my 'u' and 'dv'.
 
^If you know the formula why are you asking?
There are some variations the one you want is

$$\int_{\mathcal{V}} \! k \, (\nabla \cdot \mathbf{A}) \, \mathrm{d}\mathcal{V}=\oint_{\partial \mathcal{V}} \! k \, \mathbf{A} \, \mathrm{d}\mathcal{S}-\int_{\mathcal{V}} \! \mathbf{A} \cdot (\nabla k) \, \mathrm{d}\mathcal{V}
\\ \text{which is like}
\\ \int u \, \mathrm{d}v=u \, v-\int v \, \mathrm{d}u
\\ \text{with}
\\u=k
\\v=\mathbf{A}$$
 
iScience said:
I know the formula for integration by parts, i don't know what to do with the del operator.
I'm sorry, but you did ask:
how do i end up with the following via integration by parts?
... and the answer to that question is to follow the formula for integration by parts. Now you say you know the formula?

Please show us your best attempt using your knowledge of the formula, so that we may better understand the question.
 
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