- #1

Nikitin

- 735

- 27

Hey! Is it true that when you dot the del-operator on another vector, the differentiation has priority over the dot-product? That's why you get all those weird formulas for the divergence in circular and cylindrical coordinates (which are very different to the Cartesian ones)?

So in the case of a 2 dimensional vector in cartesian coordinates it actually goes like this?

[tex] \nabla \cdot \vec{V} = i \frac{\partial \vec{V}}{\partial x} + j \frac{\partial \vec{V}}{\partial y} [/tex]

So in the case of a 2 dimensional vector in cartesian coordinates it actually goes like this?

[tex] \nabla \cdot \vec{V} = i \frac{\partial \vec{V}}{\partial x} + j \frac{\partial \vec{V}}{\partial y} [/tex]

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