How to integrate int sin(ln(x)) ?

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Homework Statement



I am having trouble solving the following:

[tex]\int[/tex]sin(lnx) dx


The Attempt at a Solution



I let u = ln x but this makes xdu = dx so I am left with

[tex]\int[/tex]x sinu du
 
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That's the substitution you want to use,but you can't leave the x in there. If u=lnx, then x is?
 


Would x = u2?

[tex]\int[/tex]ue sin u du

Then do you do it by parts or something?
 


How on Earth did you get that? Can you solve [itex]u=\ln x[/itex] for x?
 


Oops I meant e^u, is that right?
 


Yes that's correct. You can now use integration by parts, twice.
 


does e(lnx) cancel to 1?
 


No and you should really know that at this stage! If a function has an inverse, [itex]f^{-1}(x)[/itex], then [itex]f^{-1}(f(x))=f(f^{-1}(x))=x[/itex]. So what is [itex]e^{\ln x}[/itex] and [itex]\ln e^x[/itex]?