Integrate int (sin^2(t) + cos^2(t) -1)dt from e^x to e^(2x)

cooltee13

1. The problem statement, all variables and given/known data

Integrate from e^x to e^2x: (sin^2(t) + cos^2(t) -1)dt

2. Relevant equations
just standard integral equations

3. The attempt at a solution

I know how to do most of it, my only question is: is (sin^2(e^2x) + cos^2(e^x) -1) a special trig identity? or would i just solve it like a normal interation in parts problem?

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sutupidmath

well it seems trivial to me... lol
This question seems to be just tricky, nothing else.

regor60

Aren't the sin and cos together adding to 1 the way you've written it, thus 1-1=0 ? You may want to double check you have it correct

sutupidmath

$$\int_{e^{x}}^{e^{2x}}(sin^{2}(t)+cos^{2}(t)-1)dt=\int_{e^{x}}^{e^{2x}}(1-1)dt=\int_{e^{x}}^{e^{2x}}(0)dt=?????$$

What does this equal to??

cooltee13

ok, thanks guys lol. I feel dumb now

sutupidmath

ok, thanks guys lol. I feel dumb now
Ok, integrate the following:

$$\int_0^{ln(1)} sin(x)e^{-x^{2}}dx$$

This question was somewhere i dunno where though. Give a shot to it.

HINT: THis is also tricky.

Last edited:

cooltee13

$$\int_{e^{x}}^{e^{2x}}(sin^{2}(t)+cos^{2}(t)-1)dt=\int_{e^{x}}^{e^{2x}}(1-1)dt=\int_{e^{x}}^{e^{2x}}(0)dt=?????$$

What does this equal to??

Isnt that just equal to 1?

rocomath

Look at your limits of Integration

From 0 to Ln(1)

sutupidmath

Isnt that just equal to 1?
Why on earth do u think it is equal to 1?

sutupidmath

Look at your limits of Integration

From 0 to Ln(1)
How did u change your display name?

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