How to integrate modulus function ( absolute value) within the specified limits

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To integrate the modulus of xcos(πx) from -1 to 1/2, the integral must be split based on the sign of the function within the specified limits. It is necessary to identify points where xcos(πx) changes sign, which involves determining the intervals where the function is non-negative or negative. The discussion suggests dividing the interval into four regions based on the signs of x and cos(πx). Each region will have a different integrand, and the appropriate integrand should be used for integration in those regions. This method allows for the correct evaluation of the definite integral without the use of a calculator.
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Homework Statement



integrate modulus of xcos∏x within the limits -1 to 1/2

P.S I'm not allowed to use acaluculator so graphing and finding out the answer not possible

Homework Equations



it's using the property of definite integral
∫f(x) dx within the limit from a to b = ∫f(x) dx within the limit from a to c + ∫f(x) dx within the limit from c to b

The Attempt at a Solution



i tried the problem but i don't know how to split the limits..,i.e, how to find c
 
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where is xcos(πx) non-negative?

split your interval into 4 regions:

where x < 0 and cos(πx) < 0
where x < 0 and cos(πx) ≥ 0
where x ≥ 0 and cos(πx) < 0
where x ≥ 0 and cos(πx) ≥ 0

(it may be that some of these regions are empty).

then integrate the appropriate integrand for each of the (up to) 4 regions.

for example, on a region where x is negative and the cosine is positive,

you want -∫f
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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