How to integrate modulus function ( absolute value) within the specified limits

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SUMMARY

The discussion focuses on integrating the modulus of the function \( x \cos(\pi x) \) within the limits of -1 to 1/2 without the use of calculators. Participants emphasize the importance of splitting the integral into four distinct regions based on the sign of \( x \) and \( \cos(\pi x) \). The integration technique leverages the property of definite integrals, allowing for the evaluation of the integral by analyzing the behavior of the function across these regions.

PREREQUISITES
  • Understanding of definite integrals and their properties
  • Knowledge of trigonometric functions, specifically cosine
  • Familiarity with modulus functions in calculus
  • Ability to analyze piecewise functions
NEXT STEPS
  • Study the properties of definite integrals in depth
  • Learn about piecewise functions and their integration techniques
  • Explore the behavior of trigonometric functions over different intervals
  • Practice integrating modulus functions with various examples
USEFUL FOR

Students studying calculus, particularly those tackling integration problems involving modulus functions and trigonometric expressions. This discussion is also beneficial for educators seeking to enhance their teaching methods in integral calculus.

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Homework Statement



integrate modulus of xcos∏x within the limits -1 to 1/2

P.S I'm not allowed to use acaluculator so graphing and finding out the answer not possible

Homework Equations



it's using the property of definite integral
∫f(x) dx within the limit from a to b = ∫f(x) dx within the limit from a to c + ∫f(x) dx within the limit from c to b

The Attempt at a Solution



i tried the problem but i don't know how to split the limits..,i.e, how to find c
 
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where is xcos(πx) non-negative?

split your interval into 4 regions:

where x < 0 and cos(πx) < 0
where x < 0 and cos(πx) ≥ 0
where x ≥ 0 and cos(πx) < 0
where x ≥ 0 and cos(πx) ≥ 0

(it may be that some of these regions are empty).

then integrate the appropriate integrand for each of the (up to) 4 regions.

for example, on a region where x is negative and the cosine is positive,

you want -∫f
 

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